Generate Lib From DLL

Introduction
To avoid installing and fighting against MSYS and Cygwin, you can just extract exported symbols from libvlc.dll to generate a .lib (libvlc.lib) and link your program against it.

Open Visual Studio Command Prompt
It can be found within the Visual Studio Tools menu entry:
Start / Program Files / Microsoft Visual Studio / Visual Studio Tools / Visual Studio Command Prompt.

Extract Symbols
Within the command prompt type:

dumpbin /exports "C:\Program Files\VideoLAN\VLC\libvlc.dll" > "C:\Program Files\VideoLAN\VLC\libvlc.def"

Edit the libvlc.def file and modify it to get something like this:

EXPORTS
libvlc_add_intf
libvlc_audio_get_channel
libvlc_audio_get_mute
libvlc_audio_get_track
libvlc_audio_get_track_count
libvlc_audio_get_track_description
libvlc_audio_get_volume
...

Generate the .lib
Still within the command prompt type:

lib /def:"C:\Program Files\VideoLAN\VLC\libvlc.def" /out:"C:\Program Files\VideoLAN\VLC\libvlc.lib" /machine:x86

Of course, you'll need to adapt the path according to your configuration.

Source
Generate Lib From DLL

Windows API: The relationship between Process, Handle and Windows

1)
HAVE: Process ID, NEED: Process handle
Solution: OpenProcess()

2)
HAVE: Process handle, NEED: Process ID
Solution: GetProcessId()

3)
HAVE: Window handle, NEED: Process ID
Solution: GetWindowThreadProcessId()

4)
HAVE: Window handle, NEED: Process handle
Solution: Use 3) and then 1)

5)
HAVE: Process ID, NEED: Window handle
Solution: EnumWindows(), then in the callback function do 3) and check if it matches your process ID.

6)
HAVE: Process handle, NEED: Window handle
Solution: 2) and then 5)